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Arab Club Championship Draw: Ahly and Zamalek discover opponents

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Posted on May 6, 2017

Arab Club Championship

and Zamalek learned the identities of their opponents at the 2017 , after the draw was held on Friday evening in Egypt.

In front of the pyramids and with the Minister of Youth and Sports Khaled Abdel-Aziz and CAF president Ahmad Ahmad in attendance, the draw of the 2017 Arab Championship saw Ahly and Zamalek drawn into relatively easy groups.

The draw contains 12 clubs from 10 Arab countries, split into three groups of four clubs.

The group winners will qualify for the semifinals, while the fourth berth will be for the best runner-up.

The classification for the draw was according to the geographical region for the Arab countries: Red Sea (Egypt and Sudan), North Africa (Algeria, Morocco, and Tunisia), Gulf (KSA and UAE), and the Levant (Lebanon, Jordan, and Iraq).

The draw was as follows:

Group A: Al Ahly (Egypt), Al Faisaly (Jordan), NA Hussein Dey (Algeria), Al Wehda (UAE)

Group B: Zamalek (Egypt), Fath Union Sport (Morocco), Al Nasr (KSA), Al Ahed (Lebanon)

Group C: Merrikh (Sudan), Al Hilal (KSA), Al Naft (Iraq), Espérance (Tunisia)

The tournament will be played in late summer in Egypt; two groups will be playing in Cairo, and the third will be based in Alexandria.

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